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 (1) has [be] [adv] assume that

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No Pattern Freq Relations
1 it has [be] [adv] assume that 5                    
2 [pers pn] has [be] [adv] assume that 5                    
3 it has [be] [adv] assume that 5                    
4 [pron] has [be] [adv] assume that 5                    
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