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[pron] has [be] [adv] assume that

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No Pattern Freq Relations
1 [pron] has [been] [adv] assume that 5                    
2 [pron] has be [adv] assume that 5                    
3 it has [be] [adv] assume that 5                    
4 it has [be] [adv] assume that 5                    
5 [pron] has [be] [adv] assumed that 5                    
6 [pron] has been [adv] assume that 5                    
7 [pers pn] has [be] [adv] assume that 5                    
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