Example sentences of "unc [pron] can " in BNC.
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| 1 | Consequently , we see that unc which can ( except in the case where b\a , that is where rl = 0 ) be described as " the last non-zero remainder in the above process " . |
| 2 | Since we already know that unc is equivalent to ½'we; can say that we reduce to its lowest term ½ Do you remember from page 21 the quick way of doing this type of division question ? unc You can use the same method to reduce fractions to their lowest terms , by splitting each part into its factors . |
| 3 | The product of the numerical matrices in ( 8 ) , in that order , is ( see ( 3 ) ) unc If we premultiply unc we ca finally write unc These enable us to choose , if they are required , unc but , following ( 5 ) , we could equally well use any two different linear combinations o x1 , |
| 4 | and unc we can replace the first original equation by |
| 5 | If unc we can , by the above , find m , r such that unc Then unc where |
| 6 | Similarly we deduce physical reality for the states unc Thus a proton state , on this view , is labelled by three choices of + or — " to indicate the values of the corresponding spin components in the directions unc There are eight possibilities in all : unc We can not determine experimentally all these quantities for a given proton but we can fix two of them . |
| 7 | If we revert to the original problem , the solution of Ax = x , we now see that there are just n eigenvalues s and that correspondingly there are just n vectors xs ; i.e. we have n equations unc We can combine them all into the single equation unc or more briefly AX = X where X is ow the square matrix made up of the n column vectors xs , and unc is the diagonal matrix of the eigenvalues ; and our problem is now to find the matrices X and unc for the given A. |
| 8 | In succession , we find unc Now P ( unc is the polynomial in unc unc which on differentiation gives unc We can evidently construct corresponding polynomials in the matrices B and |
| 9 | Now consider the general polynomial unc We can identify P(C) with D ; this requires unc where 1 , … , n are the diagonal elements of C , and d1 , … , dn those of D. The square matrix in ( 30 ) is known as an alternant : its reciprocal is discussed in Ref ( P1 ) . |
| 10 | However , in place of the simple unc we can drive from ( 15 ) the relation unc In practice , therefore , if convergence seems very slow , we evaluate three successive columns fully , omitting the reduction of a homologous element to unity , and solve the quadratic unc for at least two homologous elements . |
| 11 | Knowing unc we can either(i)Solve unc with one element of unc arbitrarily assigned . |
| 12 | When we have obtained unc we can perform a check , which is in any event needed when the vectors are normalised . |
| 13 | We can now deflate A. Since unc a deflated matrix A1 is unc We can therefore use A1 to obtain the remaining eigenvalues and vectors of A in the usual way . |
| 14 | Having obtained unc we can adopt it as a new unc and repeat the cycle of approximation , which is known to be quadratically convergent : i.e. if unc is the true eigenvalue , then for small differences |
| 15 | Since unc must be independent of unc we can simplify eqn ( 3.56 ) by taking |
| 16 | Study this example : unc We can save rewriting by looking out for common factors above and below the division line . |
| 17 | Therefore the area of the rectangle shown at the bottom of the last page is equal to base x height and the area of the triangle is unc We can now see that to work out the area of any triangle we simply need to remember are unc |
| 18 | unc we can use the equations you have just learnt in the following way . |
| 19 | Here is a testable prediction , all the more interesting for the fact that for appropriately chosen orientations of the axes unc one can show that quantum mechanics leads to a violation of the Bell inequality . |