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column [vb -s] [conj] you have

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No Pattern Freq Relations
1 column [vb -s] [conj] you have 5                    
2 column shows [conj] you have 5                    
3 column [vb -s] whether you have 5                    
4 column [vb -s] [subord] you have 5                    
5 column [vb -s] whether you have 5                    
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